a^2-14a+16=-8

Solution for a^2-14a+16=-8 equation:

a^2-14a+16=-8

We move all terms to the left:

a^2-14a+16-(-8)=0

We add all the numbers together, and all the variables

a^2-14a+24=0

a = 1; b = -14; c = +24;
Δ = b2-4ac
Δ = -142-4·1·24
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-10}{2*1}=\frac{4}{2}
=2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+10}{2*1}=\frac{24}{2}
=12
$